What is the derivative of f(x)=ln(sqrt(x^2-4)) ?

The derivative of f(x)=ln(sqrt(x^2-4)) is x/(x^2-4)

What is the first derivative of f(x)=ln(sqrt(x^2-4)) ?

The first derivative of f(x)=ln(sqrt(x^2-4)) is x/(x^2-4)

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derivative of

f (x) = ln (x^{2} - 4)

\frac{x}{x ^{2} - 4}

Solution steps

\frac{d}{d x} (ln (x^{2} - 4))

Apply the chain rule:

\frac{1}{x ^{2} - 4} \frac{d}{d x} (x^{2} - 4)

= \frac{1}{x ^{2} - 4} \frac{d}{d x} (x^{2} - 4)

\frac{d}{d x} (x^{2} - 4) = \frac{x}{x ^{2} - 4}

= \frac{1}{x ^{2} - 4} \cdot \frac{x}{x ^{2} - 4}

Simplify

\frac{1}{x ^{2} - 4} \cdot \frac{x}{x ^{2} - 4} : \frac{x}{x ^{2} - 4}

= \frac{x}{x ^{2} - 4}

\int (x - 1) e^{- x} d x

\frac{d ^{2}}{d x ^{2}} (6 x + 17)

t \to \infty lim (- e^{- t})

\int sin^{2} (x) \cdot cos^{4} (x) d x

\int_{0}^{2} ∣ 1 - x ∣ d x

What is the derivative of f(x)=ln(sqrt(x^2-4)) ?
The derivative of f(x)=ln(sqrt(x^2-4)) is x/(x^2-4)
What is the first derivative of f(x)=ln(sqrt(x^2-4)) ?
The first derivative of f(x)=ln(sqrt(x^2-4)) is x/(x^2-4)