What is the solution for y^{''}+y^'+4y=0,y(0)=0,y^'(0)=0 ?

The solution for y^{''}+y^'+4y=0,y(0)=0,y^'(0)=0 is y=0

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y^{''}+y^'+4y=0,y(0)=0,y^'(0)=0

y^{^{''}} + y^{^{'}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = 0

y = 0

Solution steps

y^{''} (t) + y^{'} (t) + 4 y = 0

Solve linear ODE:

y = 0

y = 0

\int sec^{3} (5 x) tan^{5} (5 x) d x

f (x) = 16 x, at x = 4

\int_{3}^{2} (5 x^{2} + 4 x + 9) d x

y^{^{''}} + 4 y = 5 sec (2 t)

y^{^{''}} (e^{x} + 1) + y^{^{'}} = 0

What is the solution for y^{''}+y^'+4y=0,y(0)=0,y^'(0)=0 ?
The solution for y^{''}+y^'+4y=0,y(0)=0,y^'(0)=0 is y=0