What is the derivative of cos(3x^2+x-1) ?

The derivative of cos(3x^2+x-1) is -sin(3x^2+x-1)(6x+1)

What is the first derivative of cos(3x^2+x-1) ?

The first derivative of cos(3x^2+x-1) is -sin(3x^2+x-1)(6x+1)

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\frac{d}{d x} (cos (3 x^{2} + x - 1))

- sin (3 x^{2} + x - 1) (6 x + 1)

Solution steps

\frac{d}{d x} (cos (3 x^{2} + x - 1))

Apply the chain rule:

- sin (3 x^{2} + x - 1) \frac{d}{d x} (3 x^{2} + x - 1)

= - sin (3 x^{2} + x - 1) \frac{d}{d x} (3 x^{2} + x - 1)

\frac{d}{d x} (3 x^{2} + x - 1) = 6 x + 1

= - sin (3 x^{2} + x - 1) (6 x + 1)

\frac{d}{d x} (ln (x) + \frac{x - 1}{x})

\int cos (- 3 x) d x

x y^{3} + 5 x y = 36, (6, 1)

\frac{\partial}{\partial x} (3 e x sin (y))

\int (x^{3} + 2) d x

What is the derivative of cos(3x^2+x-1) ?
The derivative of cos(3x^2+x-1) is -sin(3x^2+x-1)(6x+1)
What is the first derivative of cos(3x^2+x-1) ?
The first derivative of cos(3x^2+x-1) is -sin(3x^2+x-1)(6x+1)