What is the derivative of t^2+2sqrt(t)+50 ?

The derivative of t^2+2sqrt(t)+50 is 2t+1/(sqrt(t))

What is the first derivative of t^2+2sqrt(t)+50 ?

The first derivative of t^2+2sqrt(t)+50 is 2t+1/(sqrt(t))

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derivative of

t^{2} + 2 t + 50

2 t + \frac{1}{t}

Solution steps

\frac{d}{d t} (t^{2} + 2 t + 50)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{2}) + \frac{d}{d t} (2 t) + \frac{d}{d t} (50)

\frac{d}{d t} (t^{2}) = 2 t

\frac{d}{d t} (2 t) = \frac{1}{t}

\frac{d}{d t} (50) = 0

= 2 t + \frac{1}{t} + 0

Simplify

= 2 t + \frac{1}{t}

\frac{d}{d x} (t (a + b t))

y^{^{''}} + 3 y^{^{'}} + 2 y = \frac{1}{4 + e ^{x}}

x \to 2 + lim (e^{(\frac{3}{2 - x})})

\frac{d}{d x} (\frac{3 + 2 x}{5 - 8 x})

\frac{d}{d x} (3 cos (x) - cos (3 x))

What is the derivative of t^2+2sqrt(t)+50 ?
The derivative of t^2+2sqrt(t)+50 is 2t+1/(sqrt(t))
What is the first derivative of t^2+2sqrt(t)+50 ?
The first derivative of t^2+2sqrt(t)+50 is 2t+1/(sqrt(t))