What is the integral of 1/(7\sqrt[7]{x^6)} ?

The integral of 1/(7\sqrt[7]{x^6)} is \sqrt[7]{x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(7\sqrt[7]{x^6)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= \frac{1}{7} \cdot \int \frac{1}{x ^{\frac{6}{7}}} d x

Apply the Power Rule

: 7 x^{\frac{1}{7}}

= \frac{1}{7} \cdot 7 x^{\frac{1}{7}}

Simplify

Add a constant to the solution

\frac{d ^{3}}{d x ^{3}} (\frac{1}{1 - x})

\frac{d}{d x} (3 x^{2} + 2 x - 4)

\int \frac{x}{( 4 + x ^{2} )} d x

\int \frac{( 3 t - 2 )}{t + 1} d t

\frac{3}{x ^{5}}

What is the integral of 1/(7\sqrt[7]{x^6)} ?
The integral of 1/(7\sqrt[7]{x^6)} is \sqrt[7]{x}+C