What is the integral of (\sqrt[3]{x}) ?

The integral of (\sqrt[3]{x}) is 3/4 x^{4/3}+C

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integral of (\sqrt[3]{x})

\frac{3}{4} x^{\frac{4}{3}} + C

Solution steps

Apply the Power Rule

: \frac{3}{4} x^{\frac{4}{3}}

= \frac{3}{4} x^{\frac{4}{3}}

Add a constant to the solution

= \frac{3}{4} x^{\frac{4}{3}} + C

y = x^{3} - 4 x

\frac{2 - x}{e ^{3 x}}

\int \frac{x ^{2}}{( x + 2 ) ^{3}} d x

\frac{d y}{d x} = (8 + x)^{2}

\int \frac{3 x ^{2} - x + 4}{x ^{3} + 2 x ^{2} + 6 x} d x

What is the integral of (\sqrt[3]{x}) ?
The integral of (\sqrt[3]{x}) is 3/4 x^{4/3}+C