What is the integral from-infinity to 0 of 1/(7-8x) ?

The integral from-infinity to 0 of 1/(7-8x) is diverges

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integral from-infinity to 0 of 1/(7-8x)

\int_{- \infty}^{0} \frac{1}{7 - 8 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{7 - 8 x} d x

Compute the indefinite integral:

\int \frac{1}{7 - 8 x} d x = - \frac{1}{8} ln ∣ 7 - 8 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{7 - 8 x} d x =

diverges

= diverges

x \to + 2 - lim (c x^{2} + 6 x)

\int \frac{x ^{2}}{( x - 2 )} d x

y = 2 x^{4}

t e^{- t} sin (5 t)

\frac{d}{d x} (\frac{1}{2 + 3 x})

What is the integral from-infinity to 0 of 1/(7-8x) ?
The integral from-infinity to 0 of 1/(7-8x) is diverges