What is the derivative of f(t)=4t^2+5 ?

The derivative of f(t)=4t^2+5 is 8t

What is the first derivative of f(t)=4t^2+5 ?

The first derivative of f(t)=4t^2+5 is 8t

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derivative of

f (t) = 4 t^{2} + 5

8 t

Solution steps

\frac{d}{d t} (4 t^{2} + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (4 t^{2}) + \frac{d}{d t} (5)

\frac{d}{d t} (4 t^{2}) = 8 t

\frac{d}{d t} (5) = 0

= 8 t + 0

Simplify

= 8 t

3 - \frac{x ^{2}}{2}, 1, 2

y^{^{'}} + 20 y = 40 sin (60 x)

\frac{\partial}{\partial x} (sin (8 x) cos (3 y))

y = x^{2}, y = 4 x

\frac{d ^{3}}{d x ^{3}} (x sin (x))

What is the derivative of f(t)=4t^2+5 ?
The derivative of f(t)=4t^2+5 is 8t
What is the first derivative of f(t)=4t^2+5 ?
The first derivative of f(t)=4t^2+5 is 8t