What is (\partial)/(\partial x)(sin(8x)cos(3y)) ?

The answer to (\partial)/(\partial x)(sin(8x)cos(3y)) is cos(3y)cos(8x)*8

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(\partial)/(\partial x)(sin(8x)cos(3y))

\frac{\partial}{\partial x} (sin (8 x) cos (3 y))

cos (3 y) cos (8 x) \cdot 8

Solution steps

\frac{\partial}{\partial x} (sin (8 x) cos (3 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (3 y) \frac{\partial}{\partial x} (sin (8 x))

Apply the chain rule:

cos (8 x) \frac{\partial}{\partial x} (8 x)

= cos (8 x) \frac{\partial}{\partial x} (8 x)

\frac{\partial}{\partial x} (8 x) = 8

= cos (3 y) cos (8 x) \cdot 8

y = x^{2}, y = 4 x

\frac{d ^{3}}{d x ^{3}} (x sin (x))

y^{^{'}} = \frac{( y - x )}{x}

f (x) = 6 x^{- 1}

\frac{d}{d x} (cos^{2} (1 - 2 x))

What is (\partial)/(\partial x)(sin(8x)cos(3y)) ?
The answer to (\partial)/(\partial x)(sin(8x)cos(3y)) is cos(3y)cos(8x)*8