What is the derivative of sqrt(x^2-6x+9) ?

The derivative of sqrt(x^2-6x+9) is 1

What is the first derivative of sqrt(x^2-6x+9) ?

The first derivative of sqrt(x^2-6x+9) is 1

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\frac{d}{d x} (x^{2} - 6 x + 9)

1

Solution steps

\frac{d}{d x} (x^{2} - 6 x + 9)

Apply the chain rule:

\frac{1}{2 x ^{2} - 6 x + 9} \frac{d}{d x} (x^{2} - 6 x + 9)

= \frac{1}{2 x ^{2} - 6 x + 9} \frac{d}{d x} (x^{2} - 6 x + 9)

\frac{d}{d x} (x^{2} - 6 x + 9) = 2 x - 6

= \frac{1}{2 x ^{2} - 6 x + 9} (2 x - 6)

Simplify

\frac{1}{2 x ^{2} - 6 x + 9} (2 x - 6) : 1

= 1

\int_{1}^{2} \frac{1}{x ( ln ( x ) ) ^{1}} d x

\int_{1}^{\infty} \frac{1}{1 + e ^{x}} d x

2 x, 5, \frac{2}{x ^{2}}

x \to \infty lim (2 x - 4 x^{2} - 2 x)

\int \frac{1}{2 x + 2} d x

What is the derivative of sqrt(x^2-6x+9) ?
The derivative of sqrt(x^2-6x+9) is 1
What is the first derivative of sqrt(x^2-6x+9) ?
The first derivative of sqrt(x^2-6x+9) is 1