What is the derivative of sec(tan^2(x^4)) ?

The derivative of sec(tan^2(x^4)) is sec(tan^2(x^4))tan(tan^2(x^4))*8x^3sec^2(x^4)tan(x^4)

What is the first derivative of sec(tan^2(x^4)) ?

The first derivative of sec(tan^2(x^4)) is sec(tan^2(x^4))tan(tan^2(x^4))*8x^3sec^2(x^4)tan(x^4)

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\frac{d}{d x} (sec (tan^{2} (x^{4})))

sec (tan^{2} (x^{4})) tan (tan^{2} (x^{4})) \cdot 8 x^{3} sec^{2} (x^{4}) tan (x^{4})

Solution steps

\frac{d}{d x} (sec (tan^{2} (x^{4})))

Apply the chain rule:

sec (tan^{2} (x^{4})) tan (tan^{2} (x^{4})) \frac{d}{d x} (tan^{2} (x^{4}))

= sec (tan^{2} (x^{4})) tan (tan^{2} (x^{4})) \frac{d}{d x} (tan^{2} (x^{4}))

\frac{d}{d x} (tan^{2} (x^{4})) = 8 x^{3} sec^{2} (x^{4}) tan (x^{4})

= sec (tan^{2} (x^{4})) tan (tan^{2} (x^{4})) \cdot 8 x^{3} sec^{2} (x^{4}) tan (x^{4})

n = 0 \sum \infty (\frac{e}{2 π})^{n}

d y = (x y^{2} + 3 x y) d x

y^{^{''}} + 4 y^{^{'}} + 4 y = 25 cos (x)

n = 0 \sum \infty \frac{1}{3 ^{n} - n}

x^{y}

What is the derivative of sec(tan^2(x^4)) ?
The derivative of sec(tan^2(x^4)) is sec(tan^2(x^4))tan(tan^2(x^4))*8x^3sec^2(x^4)tan(x^4)
What is the first derivative of sec(tan^2(x^4)) ?
The first derivative of sec(tan^2(x^4)) is sec(tan^2(x^4))tan(tan^2(x^4))*8x^3sec^2(x^4)tan(x^4)