What is the derivative of e^x-e^{-x}-2x ?

The derivative of e^x-e^{-x}-2x is e^x+e^{-x}-2

What is the first derivative of e^x-e^{-x}-2x ?

The first derivative of e^x-e^{-x}-2x is e^x+e^{-x}-2

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derivative of

e^{x} - e^{- x} - 2 x

e^{x} + e^{- x} - 2

Solution steps

\frac{d}{d x} (e^{x} - e^{- x} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) - \frac{d}{d x} (e^{- x}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (e^{- x}) = - e^{- x}

\frac{d}{d x} (2 x) = 2

= e^{x} - (- e^{- x}) - 2

Simplify

= e^{x} + e^{- x} - 2

\int 2 x (x^{2} + 1)^{- 6} d x

f (t) = \frac{1}{( t ^{2} + 3 t + 1 ) ^{\frac{5}{2}}}

\int 1 - e^{x} d x

x \to - \infty lim (x^{3} - x)

x \to \infty lim (x^{- 6})

What is the derivative of e^x-e^{-x}-2x ?
The derivative of e^x-e^{-x}-2x is e^x+e^{-x}-2
What is the first derivative of e^x-e^{-x}-2x ?
The first derivative of e^x-e^{-x}-2x is e^x+e^{-x}-2