What is the solution for (dy)/(dx)+6/x y=-5x+9 ?

The solution for (dy)/(dx)+6/x y=-5x+9 is y=-(5x^2)/8+(9x)/7+(c_{1})/(x^6)

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(dy)/(dx)+6/x y=-5x+9

\frac{d y}{d x} + \frac{6}{x} y = - 5 x + 9

y = - \frac{5 x ^{2}}{8} + \frac{9 x}{7} + \frac{c _{1}}{x ^{6}}

Solution steps

\frac{d y}{d x} + \frac{6}{x} y = - 5 x + 9

Solve linear ODE:

y = - \frac{5 x ^{2}}{8} + \frac{9 x}{7} + \frac{c _{1}}{x ^{6}}

y = - \frac{5 x ^{2}}{8} + \frac{9 x}{7} + \frac{c _{1}}{x ^{6}}

(x + 1) \frac{d y}{d x} + (x + 2) y = 2 x e^{- x}

\int \frac{x ^{2} + 4 x}{x ^{3} + 6 x ^{2} + 5} d x

\int \frac{x + 1}{x ^{3} - x} d x

\frac{\partial}{\partial L} (K (α) (α)^{α} L^{1 - α})

y^{^{'}} + 4 y = 0

What is the solution for (dy)/(dx)+6/x y=-5x+9 ?
The solution for (dy)/(dx)+6/x y=-5x+9 is y=-(5x^2)/8+(9x)/7+(c_{1})/(x^6)