What is (\partial)/(\partial v)(2vcos(u)) ?

The answer to (\partial)/(\partial v)(2vcos(u)) is 2cos(u)

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(\partial)/(\partial v)(2vcos(u))

\frac{\partial}{\partial v} (2 v cos (u))

2 cos (u)

Solution steps

\frac{\partial}{\partial v} (2 v cos (u))

Treat

u

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 cos (u) \frac{\partial}{\partial v} (v)

Apply the common derivative:

\frac{\partial}{\partial v} (v) = 1

= 2 cos (u) \cdot 1

Simplify

= 2 cos (u)

0.882 A^{0.842}

- 8 t^{2}

f (x) = x^{\frac{1}{2}}

x \to 0 lim (\frac{1 - cos ( x )}{x})

\frac{d}{d x} (ln (4 sec (x)))

What is (\partial)/(\partial v)(2vcos(u)) ?
The answer to (\partial)/(\partial v)(2vcos(u)) is 2cos(u)