What is laplacetransform-8t^2 ?

The answer to laplacetransform-8t^2 is -(16)/(s^3)

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laplacetransform-8t^2

laplace transform

- 8 t^{2}

- \frac{16}{s ^{3}}

Solution steps

L {- 8 t^{2}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 8 L {t^{2}}

L {t^{2}} : \frac{2}{s ^{3}}

= - 8 \cdot \frac{2}{s ^{3}}

Refine

- 8 \frac{2}{s ^{3}} : - \frac{16}{s ^{3}}

= - \frac{16}{s ^{3}}

f (x) = x^{\frac{1}{2}}

x \to 0 lim (\frac{1 - cos ( x )}{x})

\frac{d}{d x} (ln (4 sec (x)))

2 t^{2} - e^{- 1}

n = 1 \sum \infty \frac{1}{4}

What is laplacetransform-8t^2 ?
The answer to laplacetransform-8t^2 is -(16)/(s^3)