What is the tangent of y= 1/(x-6),(-3,-1/9) ?

The tangent of y= 1/(x-6),(-3,-1/9) is y=-1/81 x-4/27

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tangent of y= 1/(x-6),(-3,-1/9)

tangent of

y = \frac{1}{x - 6}, (- 3, - \frac{1}{9})

y = - \frac{1}{81} x - \frac{4}{27}

Solution steps

Find the slope of

y = \frac{1}{x - 6} : \frac{d y}{d x} = - \frac{1}{( x - 6 ) ^{2}}

Compute the slope of

y = \frac{1}{x - 6}

(- 3, - \frac{1}{9}) : m = - \frac{1}{81}

Find the line with slope m=

- \frac{1}{81}

and passing through

(- 3, - \frac{1}{9}) : y = - \frac{1}{81} x - \frac{4}{27}

y = - \frac{1}{81} x - \frac{4}{27}

y^{^{'}} + 2 t y = 1

\int_{2}^{\infty} 7 x^{- 2} d x

\frac{\partial}{\partial x} (x - y^{2})

x \to 0 lim (3^{x})

\int x^{3} 7 + x^{4} d x

What is the tangent of y= 1/(x-6),(-3,-1/9) ?
The tangent of y= 1/(x-6),(-3,-1/9) is y=-1/81 x-4/27