What is the integral of zcos(z) ?

The integral of zcos(z) is zsin(z)+cos(z)+C

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integral of zcos(z)

\int z cos (z) d z

z sin (z) + cos (z) + C

Solution steps

\int z cos (z) d z

Apply Integration By Parts

: z sin (z) - \int sin (z) d z

= z sin (z) - \int sin (z) d z

\int sin (z) d z = - cos (z)

= z sin (z) - (- cos (z))

Simplify

= z sin (z) + cos (z)

Add a constant to the solution

= z sin (z) + cos (z) + C

9 y^{^{''}} + 10 y = 0, y (π) = 1

\frac{d}{d x} (9 x^{\frac{7}{5}} - 5 x^{2} + 1 0^{4})

x \to 0 + lim (- x + 7)

\frac{d ^{2} y}{d x ^{2}} = e^{5 x^{2}}

\frac{d}{d t} (\frac{tan ^{2} ( 3 t )}{t ^{2} + sec ^{2} ( t ) + 1})