What is (\partial)/(\partial y)(y-x) ?

The answer to (\partial)/(\partial y)(y-x) is 1

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(\partial)/(\partial y)(y-x)

\frac{\partial}{\partial y} (y - x)

1

Solution steps

\frac{\partial}{\partial y} (y - x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y) - \frac{\partial}{\partial y} (x)

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (x) = 0

= 1 - 0

Simplify

= 1

x = y, y^{2} - 2 y = x

y = 3 x^{2} + 2

\int (\frac{1}{2} - \frac{1}{2} cos (2 θ - \frac{π}{4})) d θ

1 + 0.2 t

\frac{d ^{4}}{d x ^{4}} (8 e^{- 4 x})

What is (\partial)/(\partial y)(y-x) ?
The answer to (\partial)/(\partial y)(y-x) is 1