What is the solution for (dy)/(dx)=(1-2/(x^2))(y-1) ?

The solution for (dy)/(dx)=(1-2/(x^2))(y-1) is y=e^{x+2/x+c_{1}}+1

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(dy)/(dx)=(1-2/(x^2))(y-1)

\frac{d y}{d x} = (1 - \frac{2}{x ^{2}}) (y - 1)

y = e^{x + \frac{2}{x} + c_{1}} + 1

Solution steps

\frac{d y}{d x} = (1 - \frac{2}{x ^{2}}) (y - 1)

Solve separable ODE:

y = e^{x + \frac{2}{x} + c_{1}} + 1

y = e^{x + \frac{2}{x} + c_{1}} + 1

\frac{\partial}{\partial y} (x^{3} y + x cos (y))

\int_{- 4}^{4} 3 (16 - y^{2}) d y

\frac{d}{d x} (\frac{2 x ^{2} + x - 3}{2 x + 7})

\int x^{2} e^{2} d x

f (x) = x^{2} + 2, (3, 11)

What is the solution for (dy)/(dx)=(1-2/(x^2))(y-1) ?
The solution for (dy)/(dx)=(1-2/(x^2))(y-1) is y=e^{x+2/x+c_{1}}+1