What is the tangent of f(x)=x^2+2,(3,11) ?

The tangent of f(x)=x^2+2,(3,11) is y=6x-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2+2,(3,11)

tangent of

f (x) = x^{2} + 2, (3, 11)

y = 6 x - 7

Solution steps

Find the slope of

f (x) = x^{2} + 2 : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(3, 11) : y = 6 x - 7

y = 6 x - 7

\frac{d y}{d x} = (3 x)

\frac{d}{d x} (cot (4 x^{2}) (x^{2} - 9))

n = 1 \sum \infty \frac{n + 4}{3 n + 2}

\int \frac{1}{x ^{2} - 4 x} d x

\int \frac{1}{( x ^{2} - 1 ) ^{\frac{1}{2}}} d x

What is the tangent of f(x)=x^2+2,(3,11) ?
The tangent of f(x)=x^2+2,(3,11) is y=6x-7