What is the integral of cos^7(x)sin^3(x) ?

The integral of cos^7(x)sin^3(x) is -(cos^8(x))/8+(cos^{10}(x))/(10)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of cos^7(x)sin^3(x)

\int cos^{7} (x) sin^{3} (x) d x

- \frac{cos ^{8} ( x )}{8} + \frac{cos ^{10} ( x )}{10} + C

Solution steps

\int cos^{7} (x) sin^{3} (x) d x

Rewrite using trig identities

= \int (1 - cos^{2} (x)) sin (x) cos^{7} (x) d x

Apply u-substitution

: \int - u^{7} (1 - u^{2}) d u

= \int - u^{7} (1 - u^{2}) d u

Expand

- u^{7} (1 - u^{2}) : - u^{7} + u^{9}

= \int - u^{7} + u^{9} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int u^{7} d u + \int u^{9} d u

\int u^{7} d u = \frac{u ^{8}}{8}

\int u^{9} d u = \frac{u ^{10}}{10}

= - \frac{u ^{8}}{8} + \frac{u ^{10}}{10}

Substitute back

u = cos (x)

= - \frac{cos ^{8} ( x )}{8} + \frac{cos ^{10} ( x )}{10}

Add a constant to the solution

= - \frac{cos ^{8} ( x )}{8} + \frac{cos ^{10} ( x )}{10} + C

\frac{d}{d x} (4 x^{2} sec (2 x))

y^{^{''}} - 2 y^{^{'}} + y = \frac{( e ^{x} )}{( 1 + x ^{2} )}

sin (4 t)

5^{- x}

\int \frac{38}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

What is the integral of cos^7(x)sin^3(x) ?
The integral of cos^7(x)sin^3(x) is -(cos^8(x))/8+(cos^{10}(x))/(10)+C