What is the derivative of (x^2-1/(x+1)) ?

The derivative of (x^2-1/(x+1)) is 1

What is the first derivative of (x^2-1/(x+1)) ?

The first derivative of (x^2-1/(x+1)) is 1

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\frac{d}{d x} (\frac{x ^{2} - 1}{x + 1})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 1}{x + 1})

Simplify

\frac{x ^{2} - 1}{x + 1} : x - 1

= \frac{d}{d x} (x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 - 0

Simplify

= 1

f (x) = 3 x^{2} + 6 x

x \to - 2 lim (3 - 5 x^{2})

\frac{\partial}{\partial x} (\frac{1}{2 π} arctan (\frac{x}{y}))

y^{^{'}} = \frac{x y}{x ^{2} - 1}

(- 7, - 9), (1, 3)

What is the derivative of (x^2-1/(x+1)) ?
The derivative of (x^2-1/(x+1)) is 1
What is the first derivative of (x^2-1/(x+1)) ?
The first derivative of (x^2-1/(x+1)) is 1