What is the derivative of f(t)=2t^2+3t-6 ?

The derivative of f(t)=2t^2+3t-6 is 4t+3

What is the first derivative of f(t)=2t^2+3t-6 ?

The first derivative of f(t)=2t^2+3t-6 is 4t+3

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derivative of

f (t) = 2 t^{2} + 3 t - 6

4 t + 3

Solution steps

\frac{d}{d t} (2 t^{2} + 3 t - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 t^{2}) + \frac{d}{d t} (3 t) - \frac{d}{d t} (6)

\frac{d}{d t} (2 t^{2}) = 4 t

\frac{d}{d t} (3 t) = 3

\frac{d}{d t} (6) = 0

= 4 t + 3 - 0

Simplify

= 4 t + 3

\frac{\partial}{\partial x} (\frac{( a x + b y )}{c x + d y})

x y^{^{''}} + y^{^{'}} = 1

\frac{\partial}{\partial x} (6 x sin (x + 2 y - z))

\frac{\partial}{\partial y} (2 x^{2} + 2 y - 8)

\int (csc^{2} (x) + 4) d x

What is the derivative of f(t)=2t^2+3t-6 ?
The derivative of f(t)=2t^2+3t-6 is 4t+3
What is the first derivative of f(t)=2t^2+3t-6 ?
The first derivative of f(t)=2t^2+3t-6 is 4t+3