What is (\partial)/(\partial y)(2x^2+2y-8) ?

The answer to (\partial)/(\partial y)(2x^2+2y-8) is 2

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(\partial)/(\partial y)(2x^2+2y-8)

\frac{\partial}{\partial y} (2 x^{2} + 2 y - 8)

2

Solution steps

\frac{\partial}{\partial y} (2 x^{2} + 2 y - 8)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x^{2}) + \frac{\partial}{\partial y} (2 y) - \frac{\partial}{\partial y} (8)

\frac{\partial}{\partial y} (2 x^{2}) = 0

\frac{\partial}{\partial y} (2 y) = 2

\frac{\partial}{\partial y} (8) = 0

= 0 + 2 - 0

Simplify

= 2

\int (csc^{2} (x) + 4) d x

\frac{d}{d x} (x^{2} \cdot e^{2 x})

\int \frac{2 ^{2 x}}{1 + 2 ^{2 x}} d x

t \frac{d y}{d t} + 4 y = t^{2}

x y^{2} y^{^{'}} = y^{3} - 5 x^{3}, y (1) = 2

What is (\partial)/(\partial y)(2x^2+2y-8) ?
The answer to (\partial)/(\partial y)(2x^2+2y-8) is 2