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Popular >

t(dy)/(dt)+4y=t^2

Solution

t \frac{d y}{d t} + 4 y = t^{2}

Solution

y = \frac{t ^{2}}{6} + \frac{c _{1}}{t ^{4}}

Solution steps

t \frac{d y}{d t} + 4 y = t^{2}

Solve linear ODE:

y = \frac{t ^{2}}{6} + \frac{c _{1}}{t ^{4}}

y = \frac{t ^{2}}{6} + \frac{c _{1}}{t ^{4}}

Graph

Popular Examples

xy^2y^'=y^3-5x^3,y(1)=2

x y^{2} y^{^{'}} = y^{3} - 5 x^{3}, y (1) = 2

tangent of f(x)=-x^2+4 tangent of

f (x) = - x^{2} + 4

derivative of sin(x)+4/5 cot(x)derivative of

sin (x) + \frac{4}{5} cot (x)

tangent of f(x)=3x^2-4x+1,\at x=2 tangent of

f (x) = 3 x^{2} - 4 x + 1, at x = 2

integral of (2u^2-2u^{-1})

\int (2 u^{2} - 2 u^{- 1}) d u

Frequently Asked Questions (FAQ)

What is the solution for t(dy)/(dt)+4y=t^2 ?
The solution for t(dy)/(dt)+4y=t^2 is y=(t^2)/6+(c_{1})/(t^4)