What is (\partial)/(\partial x)(acos(x)sin(y)) ?

The answer to (\partial)/(\partial x)(acos(x)sin(y)) is -asin(x)sin(y)

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(\partial)/(\partial x)(acos(x)sin(y))

\frac{\partial}{\partial x} (a cos (x) sin (y))

- a sin (x) sin (y)

Solution steps

\frac{\partial}{\partial x} (a cos (x) sin (y))

Treat

a, y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a sin (y) \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= a sin (y) (- sin (x))

Simplify

= - a sin (x) sin (y)

x \to 1 lim (e^{\frac{1}{1 - x}})

\frac{d}{d x} (2 x^{\frac{3}{4}})

\frac{\partial}{\partial y} (x y + z^{2})

\int 7 x sec^{2} (x) d x

\int (2 x y) d x

What is (\partial)/(\partial x)(acos(x)sin(y)) ?
The answer to (\partial)/(\partial x)(acos(x)sin(y)) is -asin(x)sin(y)