What is (\partial)/(\partial y)(xy+z^2) ?

The answer to (\partial)/(\partial y)(xy+z^2) is x

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(\partial)/(\partial y)(xy+z^2)

\frac{\partial}{\partial y} (x y + z^{2})

x

Solution steps

\frac{\partial}{\partial y} (x y + z^{2})

Treat

x, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x y) + \frac{\partial}{\partial y} (z^{2})

\frac{\partial}{\partial y} (x y) = x

\frac{\partial}{\partial y} (z^{2}) = 0

= x + 0

Simplify

= x

\int 7 x sec^{2} (x) d x

\int (2 x y) d x

\int 2 e^{- x^{2}} - 1 d x

\frac{\partial}{\partial z} (x^{\frac{y}{z}})

f (x) = 2 x^{3} \cdot ln (7 x)

What is (\partial)/(\partial y)(xy+z^2) ?
The answer to (\partial)/(\partial y)(xy+z^2) is x