What is the integral of 2e^{-x^2}-1 ?

The integral of 2e^{-x^2}-1 is sqrt(pi)\erf(x)-x+C

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integral of 2e^{-x^2}-1

\int 2 e^{- x^{2}} - 1 d x

π erf (x) - x + C

Solution steps

\int 2 e^{- x^{2}} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 e^{- x^{2}} d x - \int 1 d x

\int 2 e^{- x^{2}} d x = π erf (x)

\int 1 d x = x

= π erf (x) - x

Add a constant to the solution

= π erf (x) - x + C

\frac{\partial}{\partial z} (x^{\frac{y}{z}})

f (x) = 2 x^{3} \cdot ln (7 x)

\frac{d}{d x} (\frac{4 x ^{2} + 3}{2 x - 1})

f (x) = x^{3} + y^{3} = 16

x = 5 - 5 \cdot y^{2}, x = 5 \cdot y^{2} - 5

What is the integral of 2e^{-x^2}-1 ?
The integral of 2e^{-x^2}-1 is sqrt(pi)\erf(x)-x+C