What is the integral of 5cos(v)-7/(sqrt(1-v^2)) ?

The integral of 5cos(v)-7/(sqrt(1-v^2)) is 5sin(v)-7arcsin(v)+C

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integral of 5cos(v)-7/(sqrt(1-v^2))

\int 5 cos (v) - \frac{7}{1 - v ^{2}} d v

5 sin (v) - 7 arcsin (v) + C

Solution steps

\int 5 cos (v) - \frac{7}{1 - v ^{2}} d v

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 cos (v) d v - \int \frac{7}{1 - v ^{2}} d v

\int 5 cos (v) d v = 5 sin (v)

\int \frac{7}{1 - v ^{2}} d v = 7 arcsin (v)

= 5 sin (v) - 7 arcsin (v)

Add a constant to the solution

= 5 sin (v) - 7 arcsin (v) + C

\frac{\partial}{\partial y} (4 - x^{2} - 5 y^{2})

\frac{\partial}{\partial x} (5 e^{x})

\frac{s - 3}{s ^{2} - 4 s + 3}

x \to 0 lim (\frac{ln ( x ^{2} + 1 )}{x})

x^{2}, x - 4, - 4, 4

What is the integral of 5cos(v)-7/(sqrt(1-v^2)) ?
The integral of 5cos(v)-7/(sqrt(1-v^2)) is 5sin(v)-7arcsin(v)+C