What is the sum from n=1 to infinity of (e/n)^{2n} ?

The sum from n=1 to infinity of (e/n)^{2n} is converges

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sum from n=1 to infinity of (e/n)^{2n}

n = 1 \sum \infty (\frac{e}{n})^{2 n}

converges

Solution steps

n = 1 \sum \infty (\frac{e}{n})^{2 n}

Apply Series Root Test:

converges

= converges

\int cos^{4} (1) d x

\int 10 x ln (x + 5) d x

\int \frac{x}{8} d x

y^{^{'}} = y^{2}, y (0) = 1

y = x^{4} + 9 x^{2} - x, (1, 9)

What is the sum from n=1 to infinity of (e/n)^{2n} ?
The sum from n=1 to infinity of (e/n)^{2n} is converges