What is the slope of-3x^2+3x+1,\at x=1 ?

The slope of-3x^2+3x+1,\at x=1 is -3

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slope of-3x^2+3x+1,\at x=1

slope

- 3 x^{2} + 3 x + 1, at x = 1

- 3

Solution steps

y = - 3 x^{2} + 3 x + 1

In order to find the slope of the function, take the derivative of

- 3 x^{2} + 3 x + 1

\frac{d}{d x} (- 3 x^{2} + 3 x + 1) = - 6 x + 3

- 6 x + 3

Find the value of

- 6 x + 3

for

x = 1 : - 3

- 3

n = 0 \sum \infty (\frac{6}{5})^{- n}

f (x) = x + 1, at x = 5

\int \frac{x}{4 x - 3} d x

\int_{0}^{\frac{π}{6}} 2 sec^{3} (x) d x

\int 1 - e^{- x} d x