What is the tangent of f(x)=e^x,\at x=7 ?

The tangent of f(x)=e^x,\at x=7 is y=e^7x-6e^7

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tangent of f(x)=e^x,\at x=7

tangent of

f (x) = e^{x}, at x = 7

y = e^{7} x - 6 e^{7}

Solution steps

Find the tangent point:

(7, e^{7})

Find the slope of

f (x) = e^{x} : \frac{df ( x )}{d x} = e^{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = e^{7}

Find the line with slope m=

e^{7}

and passing through

(7, e^{7}) : y = e^{7} x - 6 e^{7}

y = e^{7} x - 6 e^{7}

\frac{d}{d x} (\frac{3 x + 5}{1 + x})

\frac{d}{d x} (3^{x} \cdot ln (3))

\int_{4}^{\infty} e^{- \frac{x}{5}} d x

a^{2} + 4 a + 5

\int \frac{1}{x ^{2} ( x ^{2} - 4 )} d x

What is the tangent of f(x)=e^x,\at x=7 ?
The tangent of f(x)=e^x,\at x=7 is y=e^7x-6e^7