What is the solution for 8x^2y^'=y^'+9xe^{-y} ?

The solution for 8x^2y^'=y^'+9xe^{-y} is y=ln(9/16 ln(8x^2-1)+c_{1})

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8x^2y^'=y^'+9xe^{-y}

8 x^{2} y^{^{'}} = y^{^{'}} + 9 x e^{- y}

y = ln (\frac{9}{16} ln (8 x^{2} - 1) + c_{1})

Solution steps

8 x^{2} y^{'} (x) = y^{'} (x) + 9 x e^{- y}

Solve separable ODE:

y = ln (\frac{9}{16} ln (8 x^{2} - 1) + c_{1})

y = ln (\frac{9}{16} ln (8 x^{2} - 1) + c_{1})

x^{2}, 12 - x, [- 3, 4]

x \to - 0 lim (e^{\frac{1}{x}})

\frac{d}{d x} (c^{1} cos (x) + c^{2} sin (x))

x \to - 4 lim (12 x + 1)

\int \frac{1}{x ln ^{2} ( x ) + 1} d x

What is the solution for 8x^2y^'=y^'+9xe^{-y} ?
The solution for 8x^2y^'=y^'+9xe^{-y} is y=ln(9/16 ln(8x^2-1)+c_{1})