What is the first derivative of kx^2 ?

The first derivative of kx^2 is 2kx

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derivative of kx^2

\frac{d}{d x} (k x^{2})

2 k x

Solution steps

\frac{d}{d x} (k x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= k \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= k \cdot 2 x^{2 - 1}

Simplify

= 2 k x

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\frac{( 2 s + 1 )}{s ( s + 1 ) ^{2}}

y = x^{s i n (x)}