What is the derivative of 3e^{-x}+e^{2x} ?

The derivative of 3e^{-x}+e^{2x} is -3e^{-x}+e^{2x}*2

What is the first derivative of 3e^{-x}+e^{2x} ?

The first derivative of 3e^{-x}+e^{2x} is -3e^{-x}+e^{2x}*2

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\frac{d}{d x} (3 e^{- x} + e^{2 x})

- 3 e^{- x} + e^{2 x} \cdot 2

Solution steps

\frac{d}{d x} (3 e^{- x} + e^{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 e^{- x}) + \frac{d}{d x} (e^{2 x})

\frac{d}{d x} (3 e^{- x}) = - 3 e^{- x}

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

= - 3 e^{- x} + e^{2 x} \cdot 2

- 5 x^{4} + 5 x^{3} - x^{2} + x

\int_{- 7}^{7} 1 + (x)^{2} d x

\int tan^{2} (3 t) d t

\frac{\partial}{\partial x} (x \cdot a + b)

y = \frac{x - 1}{x - 2} + 1, (3, 3)

What is the derivative of 3e^{-x}+e^{2x} ?
The derivative of 3e^{-x}+e^{2x} is -3e^{-x}+e^{2x}*2
What is the first derivative of 3e^{-x}+e^{2x} ?
The first derivative of 3e^{-x}+e^{2x} is -3e^{-x}+e^{2x}*2