What is the derivative of y=cos^2(t) ?

The derivative of y=cos^2(t) is -sin(2t)

What is the first derivative of y=cos^2(t) ?

The first derivative of y=cos^2(t) is -sin(2t)

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derivative of

y = cos^{2} (t)

- sin (2 t)

Solution steps

\frac{d}{d t} (cos^{2} (t))

Apply the chain rule:

2 cos (t) \frac{d}{d t} (cos (t))

= 2 cos (t) \frac{d}{d t} (cos (t))

\frac{d}{d t} (cos (t)) = - sin (t)

= 2 cos (t) (- sin (t))

Simplify

2 cos (t) (- sin (t)) : - sin (2 t)

= - sin (2 t)

\int \frac{3 x}{x ^{2} + 2} d x

f (x) = (3 x^{3})^{0.5}

\frac{\partial}{\partial y} (x y^{3} - x^{2} y)

2 x y^{^{'}} = cos^{2} (y)

9 x^{8} e^{x} + x^{9} e^{x}

What is the derivative of y=cos^2(t) ?
The derivative of y=cos^2(t) is -sin(2t)
What is the first derivative of y=cos^2(t) ?
The first derivative of y=cos^2(t) is -sin(2t)