What is the tangent of 8x-x^2(1.7) ?

The tangent of 8x-x^2(1.7) is y=(8-3.4a_{0})x+1.7a_{0}^2

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tangent of 8x-x^2(1.7)

tangent of

8 x - x^{2} (1.7)

y = (8 - 3.4 a_{0}) x + 1.7 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 8 a_{0} - a_{0}^{2} \cdot 1.7)

Find the slope of

y = 8 x - x^{2} 1.7 : \frac{d y}{d x} = 8 - 3.4 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 8 - 3.4 a_{0}

Find the line with slope m=

8 - 3.4 a_{0}

and passing through

(a_{0}, 8 a_{0} - a_{0}^{2} 1.7) : y = (8 - 3.4 a_{0}) x + 1.7 a_{0}^{2}

y = (8 - 3.4 a_{0}) x + 1.7 a_{0}^{2}

x \to 0 lim (\frac{x}{- 2 x ^{5} + 15 x})

\int (1 - x) e^{x} d x

x \to \frac{1}{2} + lim (\frac{x}{2 x - 1})

\int_{0}^{4} (5 - t) t d t

\frac{d}{d x} ((sin (2 x))^{2})

What is the tangent of 8x-x^2(1.7) ?
The tangent of 8x-x^2(1.7) is y=(8-3.4a_{0})x+1.7a_{0}^2