What is the derivative of (sin(2x)^2) ?

The derivative of (sin(2x)^2) is 2sin(4x)

What is the first derivative of (sin(2x)^2) ?

The first derivative of (sin(2x)^2) is 2sin(4x)

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\frac{d}{d x} ((sin (2 x))^{2})

2 sin (4 x)

Solution steps

\frac{d}{d x} ((sin (2 x))^{2})

Apply the chain rule:

2 sin (2 x) \frac{d}{d x} (sin (2 x))

= 2 sin (2 x) \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= 2 sin (2 x) cos (2 x) \cdot 2

Simplify

2 sin (2 x) cos (2 x) \cdot 2 : 2 sin (4 x)

= 2 sin (4 x)

\int_{- 5}^{0} ∣ x + 3 ∣ d x

\int_{1}^{4} (\frac{6}{x ^{2}}) d x

y^{^{'}} = \frac{t}{y}

x + 6, x^{2}

\frac{d}{d x} (\frac{x ^{2}}{1 + 8 x})

What is the derivative of (sin(2x)^2) ?
The derivative of (sin(2x)^2) is 2sin(4x)
What is the first derivative of (sin(2x)^2) ?
The first derivative of (sin(2x)^2) is 2sin(4x)