What is the derivative of f(x)=3x^6(x^4-7x) ?

The derivative of f(x)=3x^6(x^4-7x) is 3(10x^9-49x^6)

What is the first derivative of f(x)=3x^6(x^4-7x) ?

The first derivative of f(x)=3x^6(x^4-7x) is 3(10x^9-49x^6)

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derivative of

f (x) = 3 x^{6} (x^{4} - 7 x)

3 (10 x^{9} - 49 x^{6})

Solution steps

\frac{d}{d x} (3 x^{6} (x^{4} - 7 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{6} (x^{4} - 7 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{6}, g = x^{4} - 7 x

= 3 (\frac{d}{d x} (x^{6}) (x^{4} - 7 x) + \frac{d}{d x} (x^{4} - 7 x) x^{6})

\frac{d}{d x} (x^{6}) = 6 x^{5}

\frac{d}{d x} (x^{4} - 7 x) = 4 x^{3} - 7

= 3 (6 x^{5} (x^{4} - 7 x) + (4 x^{3} - 7) x^{6})

Expand

6 x^{5} (x^{4} - 7 x) + (4 x^{3} - 7) x^{6} : 10 x^{9} - 49 x^{6}

= 3 (10 x^{9} - 49 x^{6})

\int x^{2} - 25 d x

f (x) = (x + \frac{1}{3 x})^{2}

x \to \infty lim (e^{- 6 x} cos (x))

x y^{2} y^{^{'}} = y^{3} - 3 x^{3}, y (1) = 6

x = 8 y^{2}, x = 2 + 6 y^{2}

What is the derivative of f(x)=3x^6(x^4-7x) ?
The derivative of f(x)=3x^6(x^4-7x) is 3(10x^9-49x^6)
What is the first derivative of f(x)=3x^6(x^4-7x) ?
The first derivative of f(x)=3x^6(x^4-7x) is 3(10x^9-49x^6)