What is the derivative of (-x^2+x(-2x^2+4x-1)) ?

The derivative of (-x^2+x(-2x^2+4x-1)) is 8x^3-18x^2+10x-1

What is the first derivative of (-x^2+x(-2x^2+4x-1)) ?

The first derivative of (-x^2+x(-2x^2+4x-1)) is 8x^3-18x^2+10x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((- x^{2} + x) (- 2 x^{2} + 4 x - 1))

8 x^{3} - 18 x^{2} + 10 x - 1

Solution steps

\frac{d}{d x} ((- x^{2} + x) (- 2 x^{2} + 4 x - 1))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = - x^{2} + x, g = - 2 x^{2} + 4 x - 1

= \frac{d}{d x} (- x^{2} + x) (- 2 x^{2} + 4 x - 1) + \frac{d}{d x} (- 2 x^{2} + 4 x - 1) (- x^{2} + x)

\frac{d}{d x} (- x^{2} + x) = - 2 x + 1

\frac{d}{d x} (- 2 x^{2} + 4 x - 1) = - 4 x + 4

= (- 2 x + 1) (- 2 x^{2} + 4 x - 1) + (- 4 x + 4) (- x^{2} + x)

Simplify

(- 2 x + 1) (- 2 x^{2} + 4 x - 1) + (- 4 x + 4) (- x^{2} + x) : 8 x^{3} - 18 x^{2} + 10 x - 1

= 8 x^{3} - 18 x^{2} + 10 x - 1

cos (x^{2}) (2 x)

n = 0 \sum \infty \frac{2 n}{e ^{n}}

x \to 0 lim (\frac{( x ^{2} + 4 x )}{x})

(3 x^{2} + y - 4) - (2 y - x) y^{^{'}} = 0

2 y \cdot \frac{d y}{d x} = - x^{2}

What is the derivative of (-x^2+x(-2x^2+4x-1)) ?
The derivative of (-x^2+x(-2x^2+4x-1)) is 8x^3-18x^2+10x-1
What is the first derivative of (-x^2+x(-2x^2+4x-1)) ?
The first derivative of (-x^2+x(-2x^2+4x-1)) is 8x^3-18x^2+10x-1