What is (\partial)/(\partial x)((4xy-7)^2) ?

The answer to (\partial)/(\partial x)((4xy-7)^2) is 8y(4xy-7)

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(\partial)/(\partial x)((4xy-7)^2)

\frac{\partial}{\partial x} ((4 x y - 7)^{2})

8 y (4 x y - 7)

Solution steps

\frac{\partial}{\partial x} ((4 x y - 7)^{2})

Treat

y

as a constant

Apply the chain rule:

2 (4 x y - 7) \frac{\partial}{\partial x} (4 x y - 7)

= 2 (4 x y - 7) \frac{\partial}{\partial x} (4 x y - 7)

\frac{\partial}{\partial x} (4 x y - 7) = 4 y

= 2 (4 x y - 7) \cdot 4 y

Simplify

= 8 y (4 x y - 7)

\frac{d}{d x} (\frac{- 2}{( 6 x - 7 x ^{4} ) ^{3}})

\int (\frac{8}{x} + 8 x) d x

\frac{d}{d x} (x sec (x) tan (x))

f (x) = x + \frac{9}{x}

\frac{\partial}{\partial x} ((x y)^{z})

What is (\partial)/(\partial x)((4xy-7)^2) ?
The answer to (\partial)/(\partial x)((4xy-7)^2) is 8y(4xy-7)