What is the tangent of x^2+y^2=25,(-4,-3) ?

The tangent of x^2+y^2=25,(-4,-3) is y=-4/3 x-25/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of x^2+y^2=25,(-4,-3)

tangent of

x^{2} + y^{2} = 25, (- 4, - 3)

y = - \frac{4}{3} x - \frac{25}{3}

Solution steps

Find the slope of

x^{2} + y^{2} = 25 : \frac{d y}{d x} = - \frac{x}{y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{4}{3}

Find the line with slope m=

- \frac{4}{3}

and passing through

(- 4, - 3) : y = - \frac{4}{3} x - \frac{25}{3}

y = - \frac{4}{3} x - \frac{25}{3}

\int 2 x sin (x^{2}) d x

y^{^{'}} + \frac{y ^{2}}{x} = - \frac{1}{x}

\int \frac{x ^{2} - 1}{x ^{2} + x} d x

(x^{''})^{^{'}}

y^{^{''}} + a \cdot y^{^{'}} = b, y (0) = 0, y^{^{'}} (0) = 0

What is the tangent of x^2+y^2=25,(-4,-3) ?
The tangent of x^2+y^2=25,(-4,-3) is y=-4/3 x-25/3