What is (\partial)/(\partial x)(ln(x-2y)) ?

The answer to (\partial)/(\partial x)(ln(x-2y)) is 1/(x-2y)

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(\partial)/(\partial x)(ln(x-2y))

\frac{\partial}{\partial x} (ln (x - 2 y))

\frac{1}{x - 2 y}

Solution steps

\frac{\partial}{\partial x} (ln (x - 2 y))

Treat

y

as a constant

Apply the chain rule:

\frac{1}{x - 2 y} \frac{\partial}{\partial x} (x - 2 y)

= \frac{1}{x - 2 y} \frac{\partial}{\partial x} (x - 2 y)

\frac{\partial}{\partial x} (x - 2 y) = 1

= \frac{1}{x - 2 y} \cdot 1

Simplify

= \frac{1}{x - 2 y}

\frac{\partial}{\partial x} (sin (\frac{x}{y}))

\frac{d}{d t} (\frac{ln ( 2 t - 1 )}{t ^{2} - 1})

\frac{\partial}{\partial x} (2 x^{2} - 3 x y + z - 4)

\int (x^{2} - 6 x + 9) d x

\int \frac{2}{y ^{2}} d y

What is (\partial)/(\partial x)(ln(x-2y)) ?
The answer to (\partial)/(\partial x)(ln(x-2y)) is 1/(x-2y)