What is the derivative of-0.0000272x^2+0.008459x+440 ?

The derivative of-0.0000272x^2+0.008459x+440 is -0.0000544x+0.008459

What is the first derivative of-0.0000272x^2+0.008459x+440 ?

The first derivative of-0.0000272x^2+0.008459x+440 is -0.0000544x+0.008459

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derivative of

- 0.0000272 x^{2} + 0.008459 x + 440

- 0.0000544 x + 0.008459

Solution steps

\frac{d}{d x} (- 0.0000272 x^{2} + 0.008459 x + 440)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.0000272 x^{2}) + \frac{d}{d x} (0.008459 x) + \frac{d}{d x} (440)

\frac{d}{d x} (0.0000272 x^{2}) = 0.0000544 x

\frac{d}{d x} (0.008459 x) = 0.008459

\frac{d}{d x} (440) = 0

= - 0.0000544 x + 0.008459 + 0

Simplify

= - 0.0000544 x + 0.008459

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What is the derivative of-0.0000272x^2+0.008459x+440 ?
The derivative of-0.0000272x^2+0.008459x+440 is -0.0000544x+0.008459
What is the first derivative of-0.0000272x^2+0.008459x+440 ?
The first derivative of-0.0000272x^2+0.008459x+440 is -0.0000544x+0.008459