What is the derivative of sin(3x^3+2) ?

The derivative of sin(3x^3+2) is cos(3x^3+2)*9x^2

What is the first derivative of sin(3x^3+2) ?

The first derivative of sin(3x^3+2) is cos(3x^3+2)*9x^2

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\frac{d}{d x} (sin (3 x^{3} + 2))

cos (3 x^{3} + 2) \cdot 9 x^{2}

Solution steps

\frac{d}{d x} (sin (3 x^{3} + 2))

Apply the chain rule:

cos (3 x^{3} + 2) \frac{d}{d x} (3 x^{3} + 2)

= cos (3 x^{3} + 2) \frac{d}{d x} (3 x^{3} + 2)

\frac{d}{d x} (3 x^{3} + 2) = 9 x^{2}

= cos (3 x^{3} + 2) \cdot 9 x^{2}

\frac{d}{d x} (2 x + \frac{1}{x ^{2}})

s (t) = \frac{5}{4 t}

\frac{\partial}{\partial y} (e^{5 x y})

\int_{2}^{\infty} e^{- 8 p} d p

n = 1 \sum \infty (\frac{5}{9})^{n}

What is the derivative of sin(3x^3+2) ?
The derivative of sin(3x^3+2) is cos(3x^3+2)*9x^2
What is the first derivative of sin(3x^3+2) ?
The first derivative of sin(3x^3+2) is cos(3x^3+2)*9x^2