What is the derivative of ln(3-x) ?

The derivative of ln(3-x) is -1/(3-x)

What is the first derivative of ln(3-x) ?

The first derivative of ln(3-x) is -1/(3-x)

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\frac{d}{d x} (ln (3 - x))

- \frac{1}{3 - x}

Solution steps

\frac{d}{d x} (ln (3 - x))

Apply the chain rule:

\frac{1}{3 - x} \frac{d}{d x} (3 - x)

= \frac{1}{3 - x} \frac{d}{d x} (3 - x)

\frac{d}{d x} (3 - x) = - 1

= \frac{1}{3 - x} (- 1)

Simplify

= - \frac{1}{3 - x}

\frac{d ^{2} y}{d x ^{2}} + \frac{4}{5} \frac{d y}{d x} + \frac{8}{5} y = 0

t \to 1 lim (\frac{5 t - 1}{t + 1})

\frac{\partial}{\partial x} (\frac{a}{s} cos^{2} (x))

n = 1 \sum \infty \frac{n - 6}{n + 6}

x y^{^{'}} + y + 4 = 0

What is the derivative of ln(3-x) ?
The derivative of ln(3-x) is -1/(3-x)
What is the first derivative of ln(3-x) ?
The first derivative of ln(3-x) is -1/(3-x)