What is (\partial)/(\partial x)(3x^2+3y^2) ?

The answer to (\partial)/(\partial x)(3x^2+3y^2) is 6x

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(\partial)/(\partial x)(3x^2+3y^2)

\frac{\partial}{\partial x} (3 x^{2} + 3 y^{2})

6 x

Solution steps

\frac{\partial}{\partial x} (3 x^{2} + 3 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (3 y^{2})

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (3 y^{2}) = 0

= 6 x + 0

Simplify

= 6 x

\int (- 5) d x

\int \frac{t}{( t ^{2} + 1 ) ^{\frac{25}{2}}} d t

x^{3} + 6 x^{2} + 8 x, [- 4, 0]

\frac{\partial}{\partial x} (- x^{3} - y^{2} + 3 x^{2} - 10 y - 6)

\int \frac{1}{( 2 - x )} d x

What is (\partial)/(\partial x)(3x^2+3y^2) ?
The answer to (\partial)/(\partial x)(3x^2+3y^2) is 6x