What is the derivative of f(t)=t^2 ?

The derivative of f(t)=t^2 is 2t

What is the first derivative of f(t)=t^2 ?

The first derivative of f(t)=t^2 is 2t

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derivative of

f (t) = t^{2}

2 t

Solution steps

\frac{d}{d t} (t^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 t^{2 - 1}

Simplify

= 2 t

\frac{d}{d x} (\frac{( 4 x ^{2} + 8 x + 2 )}{x})

\frac{d}{d x} (\frac{- 3}{x})

\int x (x + 1)^{2} d x

\frac{d y}{d x} = x^{3} (x - x y)

\int \frac{1}{( x + 4 ) ( x - 1 ) ^{2}} d x

What is the derivative of f(t)=t^2 ?
The derivative of f(t)=t^2 is 2t
What is the first derivative of f(t)=t^2 ?
The first derivative of f(t)=t^2 is 2t