What is the solution for x^{''}+x=0,x(0)=0,x^'(0)=0 ?

The solution for x^{''}+x=0,x(0)=0,x^'(0)=0 is x=0

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x^{''}+x=0,x(0)=0,x^'(0)=0

x^{^{''}} + x = 0, x (0) = 0, x^{^{'}} (0) = 0

x = 0

Solution steps

x^{''} (t) + x = 0

Solve linear ODE:

x = 0

x = 0

\int_{- 4}^{4} (16 - x^{2}) d x

f (x) = x^{- 2}

\frac{d}{d x} (lo g_{10} (e^{x}))

\frac{d y}{d t} = - \frac{1}{2} y

x \to 0 + lim (\frac{x ^{2} - 1}{x})

What is the solution for x^{''}+x=0,x(0)=0,x^'(0)=0 ?
The solution for x^{''}+x=0,x(0)=0,x^'(0)=0 is x=0