What is the limit as x approaches 0+of (x^2-1)/x ?

The limit as x approaches 0+of (x^2-1)/x is -infinity

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limit as x approaches 0+of (x^2-1)/x

x \to 0 + lim (\frac{x ^{2} - 1}{x})

- \infty

Solution steps

x \to 0 + lim (\frac{x ^{2} - 1}{x})

Divide by highest denominator power:

x - \frac{1}{x}

= x \to 0 + lim (x - \frac{1}{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (x) - x \to 0 + lim (\frac{1}{x})

x \to 0 + lim (x) = 0

x \to 0 + lim (\frac{1}{x}) = \infty

= 0 - \infty

Apply Infinity Property:

c - \infty = - \infty

= - \infty

\frac{2 x - 1}{x + 1}

\frac{v - 1}{v ^{2} - 2 v + 1} d v = - \frac{1}{y} d y

\frac{\partial}{\partial x} (T x^{5} y^{4} z^{8})

\frac{1}{s ^{2} + 5 s + 2}

(\frac{3 x + 2}{x - 1})^{7}

What is the limit as x approaches 0+of (x^2-1)/x ?
The limit as x approaches 0+of (x^2-1)/x is -infinity